以下文章来源于数据结构和算法 ，作者博哥 数据结构和算法 . 《算法秘籍》作者王一博，专注于互联网大厂热点事件和算法题讲解。 有的人一找不到工作就自怨自艾，怨天尤人，一度怀疑自己，甚至破罐破摔，自甘堕落，有的甚至 为此感到焦虑，导致最后发展成了抑郁症。 实际上找不到工作并不都是你的错，而是人家已经招满了，还在继续招主要是 给公司做宣传 ，所 以这个时候你怎么可能过，就算是爱因斯坦来了一样收不到offer。下面一位网友透露出了校招的 实情，原来都是套路。 解释 ：子数组 [4,3] 是该条件下的长度最小的子数组。 示例2： 输入 ：target = 4, nums = [1,4,4] 输出 ：1 --------------下面是今天的算法题-------------- 来看下今天的算法题，这题是LeetCode的第209题：长度最小的子数组。 问题描述 来源：LeetCode第209题 难度：中等 给定一个含有 n 个正整数的数组和一个正整数 target 。找出该数组中满足其总和大于等于 target 的长度最小的连续子数组，并返回其长度。如果不存在符合条件的子数组，返回 0 。 示例1： 输入 ：targ ...

Group 1 - The article discusses a hiring scenario where a candidate with a master's degree from a prestigious university was not hired due to salary expectations exceeding the company's budget, highlighting the tension between individual salary demands and team salary balance [1][2] - It emphasizes that an individual's salary should be determined by their comprehensive abilities rather than the average salary of the team, suggesting that salary disparities are normal within teams due to varying qualifications and experiences [2] Group 2 - The article presents a coding problem from LeetCode, specifically problem 1546, which involves finding the maximum number of non-overlapping subarrays that sum to a given target [3][8] - It provides examples to illustrate the problem, showing how to identify valid subarrays and the conditions for their selection [4][6] - The solution approach involves using prefix sums and a hashmap to track the indices of sums, ensuring that selected subarrays do not overlap [8][9]